⑴﹙1/2a-b﹚-﹙1/2a+b﹚ ⑵(x^2/x-1)-x+1 ⑶﹙1/x-3﹚-﹙6/x²-9﹚-﹙x-

2个回答

  • 1)=(2a+b)/[(2a+b)(2a-b)]-(2a-b)/[(2a+b)(2a-b)]

    =[(2a+b)-(2a-b)]/[(2a+b)(2a-b)]

    =2b/[(2a+b)(2a-b)]

    =2b/(4a²-b²)

    2)=x=2(x+3)/2(x+3)(x-3﹚-12/2(x+3)(x-3)-﹙x-1)(x-3)/2(x+3)(x-3)/(x-1)-(x-1)

    =x²/(x-1)-(x-1)²/(x-1)

    =[x²-(x-1)²]/(x-1)

    =(2x-1)/(x-1)

    3)=1/(x-3﹚-6/(x+3)(x-3)-﹙x-1)/2(x+3)

    =2(x+3)/2(x+3)(x-3﹚-12/2(x+3)(x-3)-﹙x-1)(x-3)/2(x+3)(x-3)

    =[2(x+3)-12-﹙x-1)(x-3)]/2(x+3)(x-3)

    =(-x²+6x-9)/2(x+3)(x-3)

    =-(x-3)²/2(x+3)(x-3)

    =-(x-3)/2(x+3)

    =(3-x)/(2x+6)