Question

问一道数学二次函数的问题如图,二次函数Y=AX2+BX+C （A不等于0）的图像与X轴交与AB两点,与Y交于C.连接AC

Answer 1

令y = f(x) = A * x^2 + B * x^2 + C有 f(-3) = 0,f(0) = 3^0.5,f(-4) = f(2).即:9A - 3B + C = 0C = 3^0.516A - 4B + C = 4A + 2B + C解得A = -3^0.5 / 3B = -2/3 * 3^0.5C = 3^0.5所以 y = f(x) = 3^0.5 * ( -1/3*...