f(x)是奇函数且F(x+2)=-F(x)
f[log(1/2)18]
=f[-[log(2)18]
=-f[log(2)18]
=-{-f[log(2)18-2]}
=f[log(2)9/2]
=-f[log(2)9/2-2]
=-f[log(2)9/8]
log(2)9/8∈(0,1)
f[log(2)9/8]=2^[log(2)9/8]=9/8
f[log(1/2)18]=-9/8
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f(x)是奇函数且F(x+2)=-F(x)
f[log(1/2)18]
=f[-[log(2)18]
=-f[log(2)18]
=-{-f[log(2)18-2]}
=f[log(2)9/2]
=-f[log(2)9/2-2]
=-f[log(2)9/8]
log(2)9/8∈(0,1)
f[log(2)9/8]=2^[log(2)9/8]=9/8
f[log(1/2)18]=-9/8
【数学辅导团】为您解答,如果本题有什么不明白可以追问,