(2011•南充)先化简,再求值:[xx2−1
1个回答
原式=[x
x2−1(
x−1/x−
2x
x)=
x
(x+1)(x−1)]×[−x−1/x]=−
1
x−1,
当x=2时,原式=-[1/2−1]=-1.
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