化简：cos(α-π/2)/sin(5π/2+α)

化简：cos(α-π/2)/sin(5π/2+α)乘以sin(α-2π)乘以cos（2π-α）

1个回答

化简[sin(π/2-α）cos(π/2-α)]/cos(π+α)-[sin(π-α)cos(π/2-α)]/sin(π
化简[sin(π/2+α)*cos(π/2-α)]/cos(π+α)+[sin(π-α)*cos(π/2+α)]/sin
化简：（1）cos(α+π)sin(−α)cos(−3π−α)sin(−α−4π)（2）cos(α−π2)sin(5π2
化简cos(π+α)cos(π2+α)cos(11π2−α)cos(π−α)sin(−π−α)sin(9π2+α)的结果
（1）化简：sin(2π−α)cos(π+α)cos(3π2+α)cos(13π2−α)cos(π−α)sin(3π−α
化简（1）sin(α+π)cos(-α)sin(-α-π) （2）sin³（-α）cos（2π+α）tan（-
化简（1）tan(π−α)cos(2π−α)sin(−α+3π2)cos(−α−π)sin(−π−α)．
化简：（Ⅰ）sin(α−2π)cos(α+π)tan(α−99π)cos(π−α)sin(3π−α)sin(−α−π)；
化简sin(2π−α)cos(π+α)cos(π−α)sin(3π−α)sin(−α−π)=−1sinα−1sinα．
化简cos(π-α)sin(α+2π)/cos^2(-α-π)tan(2π-α