二次三项式题目!,(1)2x^2+3x=3(2)x - 知识问答

二次三项式题目!,(1)2x^2+3x=3(2)x(2x-5)=4x-10

1个回答

2x²+3x=3
2x²+3x-3=0
Δ=b²-4ac = 9+24 = 33
x=[-b±√(Δ)]/2a
所以,x1=[-3 + √33]/4
x2=[-3 - √33]/4
x(2x-5)=4x-10
2x²-5x =4x-10
2x²-9x + 10 =0
(2x-5)(x-2) =0
x1 = 5/2
x2 =2

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