(1) 0.1(2)36.8m
(1)由动能定理,有
μmgL=mv 0 2/2①
得 μ=v 0 2/(2gL)="0.1 " ②
(2) v 0="8" m/s
x 1=v 0t="8×0.6" m="4.8" m ③
由动能定理,得
μmgx 2=mv 0 2/2④
得 x 2=v 0 2/(2μg)="32" m ⑤
x= x 1+x 2="36.8" m⑥
(1) 0.1(2)36.8m
(1)由动能定理,有
μmgL=mv 0 2/2①
得 μ=v 0 2/(2gL)="0.1 " ②
(2) v 0="8" m/s
x 1=v 0t="8×0.6" m="4.8" m ③
由动能定理,得
μmgx 2=mv 0 2/2④
得 x 2=v 0 2/(2μg)="32" m ⑤
x= x 1+x 2="36.8" m⑥