x:y=1:2,y:z=3:2,2x+3y+z=56
4个回答
x:y=1:2,即y= 2x; y:z=3:2,即z=2y/3=4x/3;
2x+3y+z=56 可化为2x+6x+4x/3=56
所以x=6; y= 12; z=8;
相关问题
x+y+z=2 ① 2x+3y+z=38 ① x+y=3 3x-y-4z=5 ② 3x+4y+2z+56 ② y+z=5
2x+3y+z=48,x-2y+2z=56,3x+5y+3z=52
1、2x+y+3z=38 2、3x+2y+4z=56 3、4x+y+5z=66
证明:(y+z-2x)3+(z+x-2y)3+(x+y-2z)3=3(y+z-2x)(z+x-2y)(x+y-2z).
2x+3y+z=38 ① 3x+4y+2z=56 ② 4x+5y+z=66 ③
y=5:3 x:2=7:3 2x-y-2=34 2x+3y+z=38 3x+4y+2z=56 4x+5y+z=66
2x-y=7 x+y+z=25x+3y+z=2 x-2y+z=-1 3x-4z=4 x+2y+3z=-1x+y-z=6x
x+2y+3z=1 2x+3y+z=2 3x+y+2z=3
1.x+y+z=21,x-y=1,2x+z-y=13.2.3x+2y+z=13,x+y+2z=7 ,2z+3y-z=12
若x+y+z=2,x^2+y^2+z^2=2,1/x+1/y+1/z=1/3则 x^3+y^3+z^3=