Question

如果底数是3真数2的对数为A,则底数是6真数是根号24的对数是多少

Answer 1

log(3)2=A

log(6)24

=lg24/lg6

=lg3*2^3/lg2*3

=(lg3+lg2^3)/(lg2+lg3)

=(lg3+3lg2)/(lg2+lg3) 分子分母分别除lg3

=(1+3lg2/lg3)/(lg2/lg3+1)

=(1+3log(3)2)/(log(3)2+1)

=(1+3A)/(A+1)

=(3A+1)/(A+1)