Question

2的4n加一次方减4的2n减一次方加16的n次方的和具体过程

Answer 1

2^(4n+1)-4^(2n-1)+16^n

=2*2^4n-4^2n÷4+4^2n

=2*4^2n-4^2n÷4+4^2n

=(2-1/4+1)*4^2n

=(11/4)*4^2n

=11*4^(2n-1)