Question

大学导数简单题求导.1.y=f(x^2)2.y=f(sin^2（x）)+f（cos^2(x)）3求二阶导,y=2x^2+

Answer 1

y=f(x^2)

y'=f'(x^2)*2x

y=f(sin^2（x）)+f（cos^2(x)）

y'=f'(sin^2（x）)*(sin^2x)'+f'（cos^2(x)）*(cos^2x)'

=f'(sin^2（x）)*2sinccosx-f'（cos^2(x)）*2sinccosx

y=2x^2+lnx

y'=4x+1/x

y''=4-1/x^2