∫x/(√2x+1) dx
=∫[√2/2*(√2x+1)-√2/2]/(√2x+1)dx
=∫(√2/2-√2/2/(√2x+1))dx
=√2/2*x-1/2*ln(√2x+1)|(积分上限12,积分下限0)
=6√2-1/2*ln(12√2+1)
∫x/(√2x+1) dx
=∫[√2/2*(√2x+1)-√2/2]/(√2x+1)dx
=∫(√2/2-√2/2/(√2x+1))dx
=√2/2*x-1/2*ln(√2x+1)|(积分上限12,积分下限0)
=6√2-1/2*ln(12√2+1)