n(H2O)=2.04/18mol,n(H)=0.68/3mol.
2Na2O2+2CO2==2Na2CO3+O2,2molCO2反应,就有88g-32g=56g质量增加.那么n(CO2)=2.24/56*2mol=0.08mol.
设C2H6物质的量为n1,C3H8物质的量为n2.
2n1+3n2=0.08
6n1+8n2=0.68/3
n1=0.02mol,n2=0.04/3mol
V1:V2=n1:n2=3:2.
n(H2O)=2.04/18mol,n(H)=0.68/3mol.
2Na2O2+2CO2==2Na2CO3+O2,2molCO2反应,就有88g-32g=56g质量增加.那么n(CO2)=2.24/56*2mol=0.08mol.
设C2H6物质的量为n1,C3H8物质的量为n2.
2n1+3n2=0.08
6n1+8n2=0.68/3
n1=0.02mol,n2=0.04/3mol
V1:V2=n1:n2=3:2.