计算(1)(2+根号3)^2-(2-根号3)^2 化简1/2-根号3

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  • (1)(2+根号3)^2-(2-根号3)^2

    (2+√3)^2-(2-√3)^2

    =(4+2*2*√3+3)-(4-2*2*√3+3)

    =8√3

    (2)化简1/2-根号3

    1/(2-√3)

    =(2+√3)/(2+√3)*(2-√3)

    =(2+√3)/(4-3)

    =(2+√3)

    (3)计算(根号6-2倍根号3)^2-6(3-根号3)

    (√6-2√3)^2-6(3-√3)

    =(6-2*√6*2√3+12)-18+6√3

    =18-12√2-18+6√3

    =6(√3-2√2)

    (4)已知:根号a+根号b=根号3+根号2,根号ab=根号6-根号2,a+b=

    a+b

    =a+2√ab+b-2√ab

    =(√a+√b)^2-2√ab

    =(√3+√2)^2-2(√6-√2)

    =(3+2*√3*√2+2)-2(√6-√2)

    =5+2√6-2√6+2√2

    =5-2√2