(1)该考生恰好抽到两道化学试题的概率P1 = 1/C4取2 = 1/6
(2)该考生抽到的两道题属于不同学科的概率为5/6,并且都答对的概率P2 = 1/6*(0.6*0.7 + 2*0.6*0.6 + 2*0.7*0.7) = 53/150