Question

如图,△ABC中,AD是高,AE,BF是角平分线,它们相交于点O,∩A=60°,∩C=70°,求∩CAD,∩BOA.

Answer 1

∠CAD=180-∠C-90°=180-70-90=20°

∠ABC=180-∠C-∠CAB=180-60-70=50°

∠ABF=50/2=25°

∠BAE=(60-20)/2=20°

∠BOA=180-25-20=135°