a,b互为相反数,a+b=0
c,d互为倒数,cd=1
x的绝对值等于2,x=±2
x^2-(a+b+cd)x+(a+b)2009次方+(-cd)2010
=2^2-(0+1)x+0^2009+(-1)^2010
=4-x+0+1
=5-x
=5±2
=7或3
看懂了没,不懂再问,
a,b互为相反数,a+b=0
c,d互为倒数,cd=1
x的绝对值等于2,x=±2
x^2-(a+b+cd)x+(a+b)2009次方+(-cd)2010
=2^2-(0+1)x+0^2009+(-1)^2010
=4-x+0+1
=5-x
=5±2
=7或3
看懂了没,不懂再问,