Y=SIN²+SIN2X+2COS²X
1个回答
Y=sin2x+sin2x+2cos2x=cos2x+sin2x+1=(cos2x)/2+1/2+sin2x=根号(5/4)sin(2x+a)+1/2
不过这题数字应该有点问题.你再看看,输的对吗?
相关问题
y=sin^2x+sin2x+2cos^x
Sin x-sin y=2/3 cos x-cos y=1/2 求cos(x-y)
1.y=cos^4x+sin^4x 求周期 2.y=(sin2x+sin(2x+π/3))/( cos2x+cos(2x
下列各式中为恒等式的是( )A.sin(x+y)•sin(x-y)=sin2x-sin2yB.cos(x+y)•cos
y=sin2x+cos2x=√2*sin(2x+45°)
化简y=sin^2(x)+2sin(x)cos(x)+3cos^2(x)
tan(x+y)tan(x-y)=sin^2x-sin^2y/cos^2x-sin^2y 顺便问一下. tan,sin,
求y=sin(cos2x)cos(sin2x)的导数
当cos^2x-cos^2y=√3/2时,求sin(x+y)×sin(x-y)
有四个函数:①y=sin²x; ②y=|sinx|; ③y=(1-cos2x)/sin2x;④y=sin|x|