(2x²+ax-y+b)-(2bx²-3x+5y-1)
=2x²+ax-y+b-2bx²+3x-5y+1
=2x²-2bx²+3x+ax-y-5y+1+b
=(2-2b)x²+(a+3)x-6y+1+b
值与字母x的取值无关,则
2-2b=0 a+3=0
解得
a=-3 b=1
于是
(2b+a)^2015
=(2*1-3)^2015
=(-1)^2015
=-1
(2x²+ax-y+b)-(2bx²-3x+5y-1)
=2x²+ax-y+b-2bx²+3x-5y+1
=2x²-2bx²+3x+ax-y-5y+1+b
=(2-2b)x²+(a+3)x-6y+1+b
值与字母x的取值无关,则
2-2b=0 a+3=0
解得
a=-3 b=1
于是
(2b+a)^2015
=(2*1-3)^2015
=(-1)^2015
=-1