ln|(t-1)/(t+1)|
=ln|(t-1)(t+1) / (t+1)²|
=ln|(t-1)(t+1)|-ln|(t+1)²|
=ln|t²-1| - 2ln|t+1|
前面有个负号,一变号就是了,上下同乘x+1
有理函数的积分请问划横线处对数那部分是怎么化来的
ln|(t-1)/(t+1)|
=ln|(t-1)(t+1) / (t+1)²|
=ln|(t-1)(t+1)|-ln|(t+1)²|
=ln|t²-1| - 2ln|t+1|
前面有个负号,一变号就是了,上下同乘x+1