Question

已知函数f(x)=asin(2x+π/3)+1的定义域为R,若当(-5π/12)≤x≤(-π/12)时,f(x)的最大值

Answer 1

∵当(-5π/12)≤x≤(-π/12)时-π/2≤2x+π/3≤π/6

∴当(-5π/12)≤x≤(-π/12)时-1≤sin(2x+π/3)≤1/2

若a>0则f(x)max=a/2+1=2,∴a=2

若a