已知圆中,弦AB=L=2*(1/3^0.5),弦心距为H=1,则圆的半径R是多少?
R^2=(R-H)^2+(L/2)^2
R^2=R^2-2*H*R+H^2+L^2/4
2*H*R=H^2+L^2/4
R=H/2+L^2/(8*H)
=1/2+(2*(1/3^0.5))^2/(8*1)
=1/2+(4*(1/3))/8
=1/2+(4/3)/8
=1/2+1/6
=4/6
=2/3
已知圆中,弦AB=L=2*(1/3^0.5),弦心距为H=1,则圆的半径R是多少?
R^2=(R-H)^2+(L/2)^2
R^2=R^2-2*H*R+H^2+L^2/4
2*H*R=H^2+L^2/4
R=H/2+L^2/(8*H)
=1/2+(2*(1/3^0.5))^2/(8*1)
=1/2+(4*(1/3))/8
=1/2+(4/3)/8
=1/2+1/6
=4/6
=2/3