f(x)=1/2(cos2x-sin2x)+sin^2x 化简出来…
2个回答
f(x)=1/2(cos2x-sin2x)+sin^2x
=1/2cos2x-1/2sin2x +1/2(1-cos2x)
=1/2-1/2sin2x
相关问题
化简f(x)=(1+cos2x)sin^2x
化简(1+sin2a-cos2a)/(1+sin2a+cos2a) f(x)=根号(1+x) 化简f(sin2)-f(-
化简cos2(x)/1+sin(x) +sin2(x)/1+cos(x)
1、化简函数f(x)=(sin^4 x+cos^4 x+sin^2 xcos^2 x)/(2-sin2x)
化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x
化简f(x)=(√(sin(x/2))^4+4(cos(x/2))^2))-(√(cos(x/2))^4+4(sin(x
化简f(x)=sin(x/2)+√3cos(x/2)
化简cos3/2x*sin3/2x-cos1/2x*sin1/2x
化简:2cos2x+2sin^2 x+cos(-x)分之sin2x+sin(π-x)=___________
化简y=sin^2(x)+2sin(x)cos(x)+3cos^2(x)