|a|=4,|b|=3
1
a⊥b,则:a·b=0
2
=π/3,故:a·b=|a|*|b|*cos(π/3)=4*3/2=6
3
=0或π,则:a·b=|a|*|b|*cos(0)=12或a·b=|a|*|b|*cos(π)=-12