解由f(x)=|x|(|x-1|-|x+1|)
知f(-x)=|-x|(|-x-1|-|-x+1|)
=|x|[|-(x+1)|-|-(x-1|]
=|x|(|x+1|-|x-1|)
=-|x|(|x-1|-|x+1|)
=-f(x)
即f(-x)=-f(x)
即f(x)=|x|(|x-1|-|x+1|)是奇函数.
解由f(x)=|x|(|x-1|-|x+1|)
知f(-x)=|-x|(|-x-1|-|-x+1|)
=|x|[|-(x+1)|-|-(x-1|]
=|x|(|x+1|-|x-1|)
=-|x|(|x-1|-|x+1|)
=-f(x)
即f(-x)=-f(x)
即f(x)=|x|(|x-1|-|x+1|)是奇函数.