Question

y=x^2lnx求y' y=ln(1+x^2)求y' 1/x^2(1+x^2)dx 大家帮忙做一做

Answer 1

(1)已知y=x²lnx,求y'

dy/dx=2xlnx+x²(1/x)=2xlnx+x

(2)已知y=ln(1+x²),求y'

dy/dx=2x/(1+x²)

(3)求不定积分∫[1/x²(1+x²)]dx

∫[1/x²(1+x²)]dx =∫[(1/x²)-1/(1+x²)]dx=-(1/x)-arctanx+C