把给出的两个式子平方,求出cosxsiny和sinxcosy,再把求出的结果相加
sinx+cosy=1/3 cosx+siny=1/6 则 sin(x+y)?
3个回答
相关问题
-
已知sinx+cosy=1/3,siny+cosx=1/2,则sin(x-y)=
-
sinx-siny=-√3/3 cosx-cosy=-1/3 则cos(x-y)
-
已知sinX-sinY=-1\/2,cosX-cosY=1\/3求sin(X+Y)=?
-
sinx +siny=1/3 cosx+cosy=1/4 求tan(x+y)和sin(x+y)
-
sinx+siny=1/2,cosx+cosy=(根号3)/3,求sin[(x-y)/2]
-
证明cosx(cosx-cosy)+sinx(sinx-siny)=2sin(x-y)/2
-
sinx+siny=根号2/2 cosx+cosy=根号6/2 则sin(x+y)=
-
3sinx+4cosy=5,3cosx+4siny=-2,则sin(x+y)=
-
已知cosx+cosy=1/2,sinx-siny=1/3,则cos(x+y)=
-
若cosx*cosy+sinx*siny=1/3 ,则cos(2x-2y)=?