Question

(16-m^2)^2+4√m-2n/m+4=0,求√mn^2的值

Answer 1

16-m^2=0,m-2n=0,m+4≠0

(4-m)(4+m)=0,m-2n=0,m≠-4

m=4,m=-4,m-2n=0,m≠-4

m=4,n=2

√mn^2=√4*2^2=4