x-2y+2?,应该是x-2y+z
原式=(x-2y+z)[(x-2y+z)-(x+2y+z)]
=(x-2y+z)*(-4y)
=-4xy+8y²-4yz
（x-2y+z）的平方-（x-2y+2）(x+2y+z)
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