m^(x-1)-n^(x-2)=0→① if m=n=0,m(的2005次方)+n(的2005次方)=0;② if m=n=1,m(的2005次方)+n(的2005次方)=2;③ others:m^(x-1)-n^(x-2)=0 →m-(n/m)^(x-2)=0 →(n/m)^(x-2)=m;in the case of n>m>0,→{lim...
If the equation m(x-1)-n(x-2)for x has infinite roots,then m
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