因为25^x=2000 ,80^y=2000
所以 (25^x)^y=2000^y ,(80^y)^x=(2000)^x
即
25^xy = 2000^y (1)
80^xy = 2000^x (2)
(1)*(2)得
25^xy * 80^xy = 2000^y * 2000^x
即 2000^xy = 2000^(y+x)
即xy = x+y
所以xy-x-y = xy-(x+y)=0
因为25^x=2000 ,80^y=2000
所以 (25^x)^y=2000^y ,(80^y)^x=(2000)^x
即
25^xy = 2000^y (1)
80^xy = 2000^x (2)
(1)*(2)得
25^xy * 80^xy = 2000^y * 2000^x
即 2000^xy = 2000^(y+x)
即xy = x+y
所以xy-x-y = xy-(x+y)=0