Question

已知|x-3y-6|与(x+2y-1)²互为相反数,则x=( ),y=( )

Answer 1

已知|x-3y-6|与(x+2y-1)²互为相反数

则|x-3y-6| = -(x+2y-1)²

所以|x-3y-6| + (x+2y-1)² = 0

因为|x-3y-6|>=0,(x+2y-1)²>=0,

但|x-3y-6| + (x+2y-1)² = 0

所以x-3y-6 = 0,x+2y-1= 0

联立方程得,x=3,y= -1