Question

急求y=lntan(x/2)-cosxlntanx的导数

Answer 1

y=lntan(x/2)-cosxlntanx

dy/dx

= [1/tan(x/2)]·[1+(tan(x/2))^2]·(1/2) + (sinx)·ln(tanx) - cosx·(1/tanx)·[1+(tanx)^2]

=1/(1-cosx) + sinx(lntanx) - (1/sinx)