3x^2+2xy-y^2-16=0 ,x y 均为正整数,求x y的值
3个回答
x²+2xy+y²+2x²-2y²-16=0
(x+y)²+2(x+y)(x-y)-16=0
(x+y)(x+y+2x-2y)-16=0
(x+y)(3x-y)=16
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