∵A(2,2) 点B、C在X轴上,BC=8,AB=AC ∴ B (-2,0)C(6,0)∵A(2,2)C(6,0
∴AC的直线方程为y=-1/2X+3 ∴D(0,3)又∵A(2,2)B (-2,0 AB的直线方程为y=1/2X+1 设AB交y轴于E ∴ S△ABD=S△ADE+S△ABD =1/2*2*2+1/2*2*2=4
∵A(2,2) 点B、C在X轴上,BC=8,AB=AC ∴ B (-2,0)C(6,0)∵A(2,2)C(6,0
∴AC的直线方程为y=-1/2X+3 ∴D(0,3)又∵A(2,2)B (-2,0 AB的直线方程为y=1/2X+1 设AB交y轴于E ∴ S△ABD=S△ADE+S△ABD =1/2*2*2+1/2*2*2=4