Question

limx-o sin(2k-1)x/kx=k

Answer 1

limx-o sin(2k-1)x/kx

=1/klimx-o sin(2k-1)x/x

=1/klimx-o sin(2k-1)x/(2k-1)x/(2k-1)

=(2k-1)/klimx-o sin(2k-1)x/(2k-1)x

=(2k-1)/k=k

2k-1=k^2

k^2-2k+1=0

(k-1)^2=0

k=1