Question

已知关于x的分式方程x/(x-3)-2=m/(x-3)有正数解,试求m的取值范围.

Answer 1

x/(x-3)-2=m/(x-3)

[x-2(x-3)]/(x-3)=m/(x-3)

(-x+6)/(x-3)=m/(x-3)

-x+6=m

x=6-m

有正数解,x>0

6-m>0

m