Question

sin(xy)=x+y,求dy

Answer 1

sin(xy)=x+y 两边对x求导 cos(xy)(y+x*dy/dx)=1+dy/dx

移项变换 dy/dx (cos(xy)-1)=1-ycos(xy)

dy/dx=[1-ycos(xy)]/[xcos(xy)-1]

有 dy={[1-ycos(xy)] / [xcos(xy)-1]}*dx