Question

设函数u=f(r),r=√(x^2+y^2+z^2),则э^2u/эx^2+э^2u/эy^2+э^2u/эz^2=

Answer 1

эu/эx=f'(r)*эr/эx

=f'(r)*x/r

э^2u/эx^2=f''(r)*(x/r)^2+f'(r)*(r-x*x/r)/r^2

=f''(r)*(x/r)^2+f'(r)*(r^2-x^2)/r^3

同理

э^2u/эy^2=f''(r)*(y/r)^2+f'(r)*(r^2-y^2)/r^3

э^2u/эz^2=f''(r)*(z/r)^2+f'(r)*(r^2-z^2)/r^3

所以

э^2u/эx^2+э^2u/эy^2+э^2u/эz^2

=f''(r)*(x/r)^2+f'(r)*(r^2-x^2)/r^3+f''(r)*(y/r)^2+f'(r)*(r^2-y^2)/r^3+f''(r)*(z/r)^2+f'(r)*(r^2-z^2)/r^3

=f'(r)*(x^2+y^2+z^2)/r^2+f''(r)*[3r^2-(x^2+y^2+z^2)]/r^3

=f'(r)+2f'(r)/