f(x)=5x²-4x-3=5(x²-4x/5)-3=5[(x-2/5)²-4/25]-3=5(x-2/5)²-4/5-3=5(x-2/5)²-19/5
f(x)=-3x²+5x-8=-3(x²-5x/3)-8=-3[(x-5/6)²-25/36]-8=-3(x-5/6)²+25/12-8=-3(x-5/6)²-71/12.
f(x)=5x^2-4x-3f(x)=-3x^2+5x-8配方
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