lim(5n)-lim((an^2-bn+c)^0.5)=2
lim(5n-2)=lim((an^2-bn+c)^0.5)
根据lim的唯一性,可知
5n-2=(an^2-bn+c)^0.5
即:(5n-2)^2=an^2-bn+c
于是得:a=25,b=10
lim(5n)-lim((an^2-bn+c)^0.5)=2
lim(5n-2)=lim((an^2-bn+c)^0.5)
根据lim的唯一性,可知
5n-2=(an^2-bn+c)^0.5
即:(5n-2)^2=an^2-bn+c
于是得:a=25,b=10