∵ [a/(x+3)+b/(x-3)](x²-9)=ax-3a+bx+3b=(a+b)x+3(b-a)
∴ a+b=-5 3b-3a=9 => b-a=3 =>2b=-2 => b=-1 => a=-4
∴ a²+b²=(-4)²+(-1)²=16+1=17
∵ [a/(x+3)+b/(x-3)](x²-9)=ax-3a+bx+3b=(a+b)x+3(b-a)
∴ a+b=-5 3b-3a=9 => b-a=3 =>2b=-2 => b=-1 => a=-4
∴ a²+b²=(-4)²+(-1)²=16+1=17