设x/2=y/3=z/5=k
则
x=2k
y=3k
z=5k
则
6k+6k-5k=21
k=3
则
x=6
y=9
z=15
若x/2=y/3=z/5,且3x+2y-z=21,求x,y,z的值.
2个回答
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已知[x/3]=[y/4]=[z/5]，且2x+y-z=21，则3x+y+z=___．
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