Question

已知char **s；下面正确语句是（）A,s="ABCDEF";B,*s="ABCDEF";C,**s="ABCDEF

Answer 1

B才是对的吧不考虑类型强转并且 在此前有 s=new char*;

typedef char * pchar;

pchar *s;

s可以看成以上定义 也许更方便理解

typeid("ABCDEF").name()是const char [7];

typeid(*s).name()是char *;

typeid(**s).name()是char;

如果考虑强转可以参考如下

s=new char **;//s=(char **)(void*)("ABCDEF");

*s=new char *;//**s=(char)(long)(void*)("ABCDEF");

//*s=(char*)(long)('A');

如下操作经过VS2010 测试

char **s,**ppt,*pt,p;

cout

*s=pt=new char ;

**s=p='A';

**s=(char)(long)(void*)"A";

*s=(char*)(long)'a';

*s="B";

s=(char **)(void *)"C";

s=(char**)(void*)(long)'d';

delete ppt;

delete pt;