是x∈(π/4,π/2)吧,多了一个1
则x-π/4∈(0,π/4)
sin(x-π/4)=3/5
∴ cos(x-π/4)=4/5
∴ sin(π/4-x)=-3/5,cos(π/4-x)=4/5
∴ cos2x
=sin(π/2-2x)
=sin[2(π/4-x)]
=2sin(π/4-x)*cos(π/4-x)
=2*(-3/5)*(4/5)
=-24/25
是x∈(π/4,π/2)吧,多了一个1
则x-π/4∈(0,π/4)
sin(x-π/4)=3/5
∴ cos(x-π/4)=4/5
∴ sin(π/4-x)=-3/5,cos(π/4-x)=4/5
∴ cos2x
=sin(π/2-2x)
=sin[2(π/4-x)]
=2sin(π/4-x)*cos(π/4-x)
=2*(-3/5)*(4/5)
=-24/25