Question

已知函数y=5x-1,x∈{0,1,2,3,4,5},求f(2),f(4)及函数的值域.

Answer 1

f(2)=2×5-1=9

f(4)=4×5-1=19

y的值域为{f(0),f(1),f(2),f(3),f(4),f(5）}={-1,4,9,14,19,24}