4/(1x3)+4/(3x5)+4/(5x7)+...+4/(19x20)=多少?
1个回答
4/(1x3)+4/(3x5)+4/(5x7)+...+4/(19x21)
=2/1-2/3+2/3-2/5+2/5-2/7+...+2/19-2/21
=2-2/21
=40/21
相关问题
(2X2)/1X3+(4X4)/(3X5)+(6X6)/(5X7)+...+(20X20)/(19X21)==?
观察下列单项式:1/2x,-2/3x^2,3/4x^3,-4/5x^4,5/6x^5,…,19/20x^19,-20/2
5/(1x2x3x4)+7/(2x3x4x5)+9/(3x4x5x6)+...+37/(17x18x19x20)
3x4+4x5+5x6+.19x20+20x21=?
(4)1/6(3x-6)=2/5x-3 (5)3(x-7)+5(x-4)=15 (6)4x-3(20-x)=-4
已知5x+4.3=19.3,那么2x+4.7=多少
19.解方程.3-5x=2x+9 20.解方程.7(2x-1)-3(4x-1)=4(3x+2)-1
1x2/1+2x3/1+3x4/1+4x5/1.19x20/1
2(x+3)-5(1-x)=3(3-1) 4-3(2-x)=5x 4x-3(20-x)=6x-7(9-x) 4-3(2-
4x+20=76 3x-15=27 7x-3乘5=55 7x+2=4.5 4x-1.5x=22.5 2(x-1.3)=8