(3χ-2χ+1)÷(χ₃-3χ₂-χ-1)
2个回答
(3χ-2χ+1)÷(χ³-3χ²-χ-1)
=(χ+1)÷(χ³-3χ²-χ-1)
=x^4-3x³-x²-x+x³-3x²-x-1
=x^4-2x³-4x²-2x-1
相关问题
χ²-χ/2(χ+1)+χ/3(χ-1)+χ/6(χ-2)
化简:χ(χ²-1)+2χ²(χ+1)-3χ(2χ-5).
χ-(3χ-1)≤χ+2
1.解方程①(2χ-1﹚²=3 ②χ²-25=0 ③3﹙χ-2﹚²=χ﹙χ-2﹚ ④﹙χ-5﹚﹙2χ-1﹚=32..已知
2χ-1/3(χ+1)=4χ-(2χ+50%)
用因式分解法解下列方程: 1. 3χ﹙χ-1﹚=2﹙χ-1﹚ 2.﹙2χ-1﹚²=﹙3-χ﹚²
解方程:9÷ 3/4 χ = 1/3 χ-3/5 χ= 6/5 1-25%χ=0.5
3.5×2/3χ+2×1/3χ-2.5χ=70 3.5×2/3χ+2×1/3χ-2.5χ=70
已知5χ+0.8=19.3,那么2χ-1.4=( ),()÷χ=2
如果3χ=b,b+χ=() A.2χ B.8χ C.4χ