已知5×a-2的绝对值+3【b+1]²=0求5ab²-2a²b-](4ab²-2a²b)]的值,求正解!
5×Ia-2I+3【b+1]²=0
a-2=0
a=2
b+1=0
b=-1
5ab²-2a²b-](4ab²-2a²b)]
=5*2*(-1)²-2*2²(-1)-](4*2*(-1)²-2*2²(-1))]
=10+8-I8+8I
=18-16
=2
已知5×a-2的绝对值+3【b+1]²=0求5ab²-2a²b-](4ab²-2a²b)]的值,求正解!
5×Ia-2I+3【b+1]²=0
a-2=0
a=2
b+1=0
b=-1
5ab²-2a²b-](4ab²-2a²b)]
=5*2*(-1)²-2*2²(-1)-](4*2*(-1)²-2*2²(-1))]
=10+8-I8+8I
=18-16
=2