Question

化简代数式m²-1/m²+2m÷(2-(1+m/m)),并判断当m满足不等式组m+2＜1,2（m-1

Answer 1

(m²-1)/(m²+2m) ÷ [2-(1+m)/m]

=(m+1)(m-1)/[m(m+2)] ÷[(2m-1-m)/m]

=(m+1)(m-1)/[m(m+2)] × m/(m-1)

=(m+1)/(m+2)

解不等式m+2＜1得：m-3,即m>-2

所以满足不等式组的m的解为：-2